Capacitor bank

Description

In industrial units, since most of their consumption is self-contained, therefore, in addition to active power, reactive power is used. For example, the coil of electric motors consumes both active or useful power and reactive or non-useful power to do the work and rotate the motor, as a result, it increases the line current and also increases the power loss and the power factor. This phenomenon causes the amount of power that the source must produce to be more than the consumer’s needs. Therefore, on behalf of the electricity department, we will be fined for the losses and losses of the fog that we have introduced into the network, which will incur exorbitant costs.

Therefore, in order to reduce the line current and voltage drop, increase the power factor, and as a result, compensate for the reactive power, the capacitor is used. This act of modifying the power factor is called.

The power factor is obtained by dividing the active power by the apparent power:

COSφ= P/S

In the power triangle, it can be seen that as the angle φ gets closer to zero, COSφ gets closer to one, which causes the reactive power to decrease.

Finally, if COS0° becomes equal to one:

COSφ= P/S => COSφ= 1

It means that the active power is equal to the apparent power, that is, the two sides of this triangle coincide and this has caused our reactive power to be zero.